Don't use 0 as null pointer constant, part 3
This part replaces E == 0 by !E, where E has pointer type.
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79 changed files with 121 additions and 121 deletions
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@ -41,8 +41,8 @@ onearg(char *arg, char *prompt)
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int n;
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char buf[1024];
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if (arg == 0 || *arg == 0) {
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if ((arg = getstring(prompt, buf)) == 0)
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if (!arg || !*arg) {
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if (!(arg = getstring(prompt, buf)))
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return -1;
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}
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n = atoi(arg);
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