New show product
This is the human-readable buddy of xdump product, which dumps pchr[]. It duplicates much of the information in show sect c, but in more accessible form. It's in show_product(). Remove product information from info Quick-ref. show reflects the actual game, is more complete, and should be just as readable.
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7 changed files with 101 additions and 136 deletions
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@ -652,6 +652,7 @@ extern void show_sect_stats(int);
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extern void show_sect_capab(int);
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extern void show_item(int);
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extern void show_news(int);
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extern void show_product(int);
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extern void show_updates(int);
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/* shpsub.c */
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extern void shp_sel(struct nstr_item *, struct emp_qelem *);
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160
info/Products.t
160
info/Products.t
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@ -8,121 +8,65 @@ Some of those products may, in turn,
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be considered raw materials for other industries
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which produce other products.
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.s1
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This table gives the constituents and costs for each type of product.
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The show command displays characteristics of products:
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.s1
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All costs given in the table are for 100% production efficiency.
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Many processes depend on technology level
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or educational level of the country;
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a note like \*Qp.e.=(tlev+10)/(tlev+20)\*U means
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that a country with a technology level of 0
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has a production efficiency of 50%
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and will only produce one-half of the specified product amount
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for the given costs,
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whereas a country with a technology level of 100
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will have a production efficiency of 92%.
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.EX show product
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.NF
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product cost raw materials reso dep level p.e.
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iron i $0 min 0 1.0
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dust d $0 gold 20 1.0
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food f $0 fert 0 (tech+10)/(tech+20)
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oil o $0 ocont 10 (tech+10)/(tech+20)
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rad r $2 uran 35 (tech-40)/(tech-30)
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shells s $3 2l 1h (tech-20)/(tech-10)
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guns g $30 1o 5l 10h (tech-20)/(tech-10)
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petrol p $1 1o (tech-20)/(tech-10)
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bars b $10 5d 1.0
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lcm l $0 1i (tech+10)/(tech+20)
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hcm h $0 2i (tech+10)/(tech+20)
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tech $300 1d 5o 10l (educ-5)/(educ+5)
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medical $90 1d 5o 10l (educ-5)/(educ+5)
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edu $9 1l 1.0
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happy $9 1l 1.0
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.FI
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.s1
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In addition, some sectors don't produce raw materials as well as others,
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and some produce much better than others. Use the "show sector capabilities"
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command to see production efficiencies and other useful information on
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producing sectors.
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The columns are:
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.in \w'raw materials\0\0'u
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.L product
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The name of the product and the one-letter mnemonic of the commodity
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made, if any.
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.L cost
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Cost per unit of production.
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.L "raw materials"
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Raw materials for one unit of production.
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.L "reso dep"
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Natural resource exploited, and its rate of depletion.
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.L "level p.e."
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Level production efficiency, for 100% sector type production
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efficiency
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.in
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.s1
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The rate at which constituents can be turned into products
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How much a sector can produce
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is governed by the amount of \*Qwork\*U performed by its populace,
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divided by the units of constituents
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per unit of product.
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divided by the amount of raw materials
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per unit of production.
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E.g., it takes 3 units of \*Qwork\*U to produce 1 shell;
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2 units to incorporate the light construction materials
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and 1 unit for the heavy.
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\*QNatural resources\*U such as fertility
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count as one unit of constituents;
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Mining a \*Qnatural resource\*U such as fertility
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takes one unit of work;
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e.g., it takes 1 unit of work per unit of food produced.
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.s1
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.in \w'technology\0\0'u
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.L shells
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Shell production efficiency depends on technology level;
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p.e.=(tlev-20)/(tlev-10)
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Shells cost $3 each to manufacture.
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Each requires 2 units of light construction materials
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and 1 unit of heavy construction materials.
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You must have a minimum technology of 20 to produce shells.
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.L guns
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Gun production depends on technology level;
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p.e.=(tlev-20)/(tlev-10)
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Guns cost $30 each to manufacture.
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Each requires 5 units of light construction materials,
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10 units of heavy construction materials,
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and 1 unit of oil.
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You must have a minimum technology of 20 to produce guns.
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.L iron
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Iron ore production depends on the mine's mineral richness.
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Extracting iron ore is free,
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and doesn't deplete the sector's mineral richness.
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.L dust
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Gold dust production depends on the mine's gold richness.
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Extracting gold dust is free,
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but depletes the sector's gold richness.
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.L bars
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Gold bars cost $10 to produce and require 5 units of gold dust each.
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.L food
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Food production efficiency depends on technology level
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and the fertility of the sector;
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p.e.=(tlev+10)/(tlev+20).
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Growing food is free,
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and doesn't deplete the sector's fertility.
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.L oil
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Oil production efficiency depends on technology level
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and the oil content of the sector;
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p.e.=(tlev+10)/(tlev+20).
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Pumping oil is free,
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but depletes the sector's oil content.
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.L petrol
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Petrol production depends on technology level;
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p.e.=(tlev-20)/(tlev-10).
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A unit of petrol costs $1 to manufacture.
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Every 10 units of petrol require 1 unit of oil to produce.
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You must have a minimum technology of 20 to produce petrol.
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.L lcm
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Light construction material production efficiency
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depends on technology level;
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p.e.=(tlev+10)/(tlev+20).
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Producing lcms does not cost money, but requires 1 unit of iron ore.
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.L hcm
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Heavy construction material production efficiency
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depends on technology level;
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p.e.=(tlev+10)/(tlev+20).
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Producing hcms does not cost money, but requires 2 unit of iron ore.
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.L rad
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Radioactive material production efficiency depends on technology level,
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which must be at least 40.
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p.e.=(tlev-40)/(tlev-30).
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Producing rads cost $2 per ton,
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and depletes the uranium content of the sector.
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.L education
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A unit of education (a \*Qclass of graduates\*U),
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costs $10 to produce and requires 1 unit
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of light construction materials (see "info Education").
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.L happiness
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A unit of happiness (\*Qhappy strollers\*U),
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costs $10 to produce and requires 1 unit
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of light construction materials (see "info Happiness").
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.L technology
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Technology production efficiency depends on education level;
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p.e.=(elev-5)/(elev+5).
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A unit of technology (a \*Qtechnological breakthrough\*U),
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costs $5 times the number of ETUs per update
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to produce, and requires 10 units
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of light construction materials,
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5 units of oil and 1 unit of gold dust. For more details about how
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technology level is calculated from technology units, see "info Technology".
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.L research
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Research production efficiency depends on education level;
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p.e.=(elev-5)/(elev+5).
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A unit of research (a \*Qmedical discovery\*U),
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costs $90 to produce and requires 10 units
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of light construction materials,
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5 units of oil and 1 unit of gold dust (see "info Research").
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How many products each unit of production makes depends on the level
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production efficiency, which is the product's level p.e. (shown by
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"show product") times the sector type's p.e. (shown by "show sect
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stats"). Production requires a level p.e. above zero, obviously.
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.s1
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Note that the resource depletion documented above can be customized by
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the deity.
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.in
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.SA "Producing, Updates"
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Say your country is at tech level 25. Then your agribusinesses' level
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p.e. is (25+10)/(25+20) * 900% = 7, i.e. they'll make 7 food per unit
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of production. Your shell industries' level p.e. is only
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(25-20)/(25-10) * 100% = 1/3, i.e. they'll make 1 shell per three
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units of production. Your uranium mines can't produce at all, because
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their level p.e. is negative.
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.s1
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.SA "Producing, Updates, Item-types"
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@ -1,8 +1,7 @@
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.TH Concept "Quick Reference Card"
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.NA Quick-ref "A quick reference card for sector types and production"
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.NA Quick-ref "A quick reference card for sector types"
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.LV Basic
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.NF
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Sector-types:
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BASICS INDUSTRIES MILITARY / SCIENTIFIC
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. sea d defense plant t technical center
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@ -18,25 +17,5 @@ Sector-types:
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j light manufacturing
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# bridge head k heavy manufacturing
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= bridge span % refinery
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(Petrol is per 10 units; others per unit)
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Products:
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Item $ Lcm Hcm Iron Dust Oil Rad Tech Production Eff.
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Shells: 3 2 1 0 0 0 0 20 (tech-20)/(tech-10)
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Guns: 30 5 10 0 0 1 0 20 (tech-20)/(tech-10)
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Iron: 0 0 0 0 0 0 0 0 0
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Dust: 0 0 0 0 0 0 0 0 0
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Bars: 10 0 0 0 5 0 0 0 0
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Food: 0 0 0 0 0 0 0 0 (tech+10)/(tech+20)
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Oil: 0 0 0 0 0 0 0 0 (tech+10)/(tech+20)
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Petrol 1 0 0 0 0 1 0 20 (tech-20)/(tech-10)
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Lcm: 0 0 0 1 0 0 0 0 (tech+10)/(tech+20)
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Hcm: 0 0 0 2 0 0 0 0 (tech+10)/(tech+20)
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Rad: 2 0 0 0 0 0 0 40 (tech-40)/(tech-30)
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Educate: 9 1 0 0 0 0 0 0 0
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Happy: 9 1 0 0 0 0 0 0 0
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Tech: 5*ETUS 10 0 0 1 5 0 0 (edu-5)/(edu+5)
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Resrch: 90 10 0 0 1 5 0 0 (edu-5)/(edu+5)
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.FI
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.SA "Sectors, Producing"
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.SA "Sectors"
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@ -2,11 +2,11 @@
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.NA show "Characteristics of sectors, units, updates and more"
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.LV Basic
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.SY "show <land|nuke|plane|sector|ship> [b|s|c] [tech]"
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.SY "show <bridge|item|news|tower>"
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.SY "show <bridge|item|news|product|tower>"
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.SY "show <updates> [number]"
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The show command shows characteristics of sectors, units (ships,
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planes, land units and nukes), bridges (spans and towers), items and
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news, as well as information on updates.
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planes, land units and nukes), bridges (spans and towers), items, news
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and products, as well as information on updates.
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.s1
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Characteristics are more fully described in separate info
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pages (Ship-types, Nuke-types, etc.).
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@ -36,4 +36,4 @@ Printing for tech level '325'
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75kt fusion 3 90 3 320 106 $ 20000
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.FI
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.s1
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.SA "Ship-types, Nuke-types, Plane-types, Unit-types, Sector-types, Ships, Planes, LandUnits, Nukes, Bridges, Item-types, newspaper, Updates"
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.SA "Ship-types, Nuke-types, Plane-types, Unit-types, Sector-types, Ships, Planes, LandUnits, Nukes, Bridges, Item-types, Products, newspaper, Updates"
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@ -98,6 +98,10 @@ show(void)
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cfunc = show_land_capab;
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break;
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case 'p':
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if (p[1] == 'r') {
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show_product(99999);
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return RET_OK;
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}
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bfunc = show_plane_build;
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sfunc = show_plane_stats;
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cfunc = show_plane_capab;
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@ -230,7 +230,7 @@ struct cmndstr player_coms[] = {
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{"ship <SHIPS>", 0, shi, 0, NORM},
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{"shoot <c|u> <SECTS> <NUMBER>", 3, shoo, C_MOD, NORM + MONEY + CAP},
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{"show <TYPE> <\"build\"|\"stats\"|\"cap\"> [<tech>]\n"
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"\tshow <bridge|item|news|tower>\n"
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"\tshow <bridge|item|news|product|tower>\n"
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"\tshow updates [<NUM>]>",
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0, show, 0, VIS},
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{"shutdown <minutes> <disable update?>", 0, shut, 0, GOD},
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@ -597,6 +597,43 @@ show_item(int tlev)
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}
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}
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void
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show_product(int tlev)
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{
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struct pchrstr *pp;
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int i;
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char *lev;
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pr("product cost raw materials reso dep level p.e.\n");
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for (pp = pchr; pp->p_sname; pp++) {
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pr("%7.7s %c $%-3d ",
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pp->p_sname,
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pp->p_type < 0 ? ' ' : ichr[pp->p_type].i_mnem,
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pp->p_cost);
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(void)CANT_HAPPEN(MAXPRCON > 3); /* output has only three columns */
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for (i = 0; i < 3; i++) {
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if (i < MAXPRCON && pp->p_camt[i]
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&& pp->p_ctype[i] > I_NONE && pp->p_ctype[i] <= I_MAX)
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pr(" %2d%c", pp->p_camt[i], ichr[pp->p_ctype[i]].i_mnem);
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else
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pr(" ");
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}
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if (pp->p_nrndx)
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pr(" %5.5s %3d ",
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symbol_by_value(pp->p_nrndx, resources), pp->p_nrdep);
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else
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pr(" ");
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if (pp->p_nlndx < 0)
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pr("1.0\n");
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else {
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lev = symbol_by_value(pp->p_nlndx, level);
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pr("(%.4s%+d)/(%.4s%+d)\n",
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lev, -pp->p_nlmin, lev, pp->p_nllag - pp->p_nlmin);
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}
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}
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}
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void
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show_news(int tlev)
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{
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