2 * Empire - A multi-player, client/server Internet based war game.
3 * Copyright (C) 1986-2011, Dave Pare, Jeff Bailey, Thomas Ruschak,
4 * Ken Stevens, Steve McClure, Markus Armbruster
6 * Empire is free software: you can redistribute it and/or modify
7 * it under the terms of the GNU General Public License as published by
8 * the Free Software Foundation, either version 3 of the License, or
9 * (at your option) any later version.
11 * This program is distributed in the hope that it will be useful,
12 * but WITHOUT ANY WARRANTY; without even the implied warranty of
13 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
14 * GNU General Public License for more details.
16 * You should have received a copy of the GNU General Public License
17 * along with this program. If not, see <http://www.gnu.org/licenses/>.
21 * See files README, COPYING and CREDITS in the root of the source
22 * tree for related information and legal notices. It is expected
23 * that future projects/authors will amend these files as needed.
27 * stmtch.c: Matching operations on structures and commands
29 * Known contributors to this file:
30 * Markus Armbruster, 2004-2010
38 * Find element named NEEDLE in array HAYSTACK[], return its index.
39 * Return M_NOTFOUND if there are no matches, M_NOTUNIQUE if there are
41 * Each array element has a pointer to its name stored at offset OFFS.
42 * Search stops when this name is a null pointer.
43 * It ignores elements with an empty name.
44 * NEEDLE is compared to element names with mineq(NEEDLE, NAME).
45 * SIZE gives the size of an array element.
48 stmtch(char *needle, void *haystack, ptrdiff_t offs, size_t size)
55 name = *(char **)((char *)haystack + i * size + offs);
60 switch (mineq(needle, name)) {
64 if (res == M_NOTFOUND)
78 * Return ME_EXACT if they are the same, or A is a prefix of B
79 * followed by a space in B.
80 * Return ME_PARTIAL if A is a prefix of B not followed by a space.
81 * Else return ME_MISMATCH.
84 mineq(char *a, char *b)
88 /* find common prefix: */
89 for (i = 0; a[i] != 0 && a[i] == b[i]; i++) ;
93 if (b[i] == 0 || b[i] == ' ')